15 moles of H 2 and 5.2 moles of I 2 are mixed and allowed to attain equilibrium at 50 0 ∘ C . At equilibrium, the concentration of HI is found to be 10 moles. The equilibrium constant for the for

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15 moles of H 2 ​ and 5.2 moles of I 2 ​ are mixed and allowed to attain equilibrium at 50 0 ∘ C . At equilibrium, the concentration of HI is found to be 10 moles. The equilibrium constant for the formation of HI is:

TestHub · Accepted Answer

H 2 ​ + I 2 ​ ⇌ 2 H I : Initially, 15 5.2 0 At equilibrium, 15 − x 5.2 − x 2 x Given 2 x = 10 , I 2 ​ = 5.2 − 5 = 0.2 H I = 10 Hence K c ​ is given by: K c ​ = [ H 2 ​ ] [ I 2 ​ ] [ H I ] 2 ​ K c ​ = ( 10 ) ( 0.2 ) ( 10 ) 2 ​ = 2 100 ​ = 50

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