For the single-step reaction 2NO 2 (g) ⇌ N 2 O 4 (g), the rate law expression is:

Forward step is elementary, so its rate is k 1 [NO 2 ] 2 and the reverse rate is k -1 [N 2 O 4 ] Rate of reaction = k 1 [NO 2 ] 2 - k -1 [N 2 O 4 ] Two moles of NO 2 are consumed per event, so -1/2(d[NO 2 ])/dt equals the rate of reaction This is option (b).

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ChemistryChemical EquilibriumProblems involving KcMedium2 minQB

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For the single-step reaction 2NO₂(g) ⇌ N₂O₄(g), the rate law expression is:

Options:

Answer:

Solution:

Forward step is elementary, so its rate is k₁[NO₂]² and the reverse rate is k_-1[N₂O₄] Rate of reaction = k₁[NO₂]² - k_-1[N₂O₄]

Two moles of NO₂ are consumed per event, so -1/2(d[NO₂])/dt equals the rate of reaction

This is option (b).

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kc

⏱ 2mℹ️ Source: QB

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