Chemistry - Chemical Equilibrium Question with Solution | TestHub
The left chamber holds NH4HS(s), NH3(g), H2S(g) and He(g) at equilibrium and the right chamber holds He(g). A fixed semipermeable membrane (SPM) between them allows only He(g) to cross.
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The entire system is at equilibrium at 400 K. The volume of each chamber is 41.0 L. The total pressure in the left chamber is 5 atm and in the right chamber, 1 atm. NH3(g) and H2S(g) are obtained only from the dissociation of NH4HS(s). The value of KP (in atm2) for the reaction: NH4HS(s) ⇌ NH3(g) + H2S(g), is
Answer:
Solution:
The fixed semipermeable membrane allows only He(g) to cross, so He has equal partial pressure on both sides Right chamber has only He, so PHe = 1 atm in both chambers
Left chamber: PNH3 + PH2S = 5 - 1 = 4 atm
NH3 and H2S form in equal amounts, so each is 2 atm
KP = (PNH3)(PH2S) = (2)(2)
KP = 4 atm2
