Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumProblems involving KcHard2 minQB
ChemistryHardsingle choice
The complexation Ni2+ + 3 en ⇌ [Ni(en)3]2+ was studied at 25°C. The forward rate is (2.0×1012 M-3s-1)[Ni2+][en]3 and the reverse rate is (4.0×10-3 s-1)[Ni(en)32+]. The stability constant of the complex is
Options:
Answer:
A
Solution:
At equilibrium, the forward rate equals the reverse rate. The stability constant, Kstab, is given by:
Kstab = ([Ni(en)32+])/([Ni2+][en]3) = (kf)/(kb)
Given the values, we can calculate Kstab:
Kstab = (2.0 ×1012)/(4.0 ×10-3) = 5.0 ×1014 M-3
This corresponds to option (a).
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kc
⏱ 2mℹ️ Source: QB
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