A gas X (molecular mass M) dissociates as: X(g) ⇌ 2Y(g) + Z(g). If the total pressure of the system at equilibrium is P and the density is d at temperature T K, the degree of dissociation of X is

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TestHub · Accepted Answer

One mole of X gives 1 - α + 2α + α = 1 + 2α moles at equilibrium The mean molar mass of the mixture is M_mix = M/(1 + 2α)

For an ideal gas d = PM_mix/RT

d = PM/[(1 + 2α)RT]

1 + 2α = PM/(dRT)

α = (PM - dRT)/(2dRT)

This is option (c).

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