15 moles of H 2 and 5.2 moles of I 2 are mixed and allowed to attain equilibrium at 50 0 ∘ C . At equilibrium, the amount of HI is found to be 10 moles. The equilibrium constant for the formation

Question

15 moles of H 2 ​ and 5.2 moles of I 2 ​ are mixed and allowed to attain equilibrium at 50 0 ∘ C . At equilibrium, the amount of HI is found to be 10 moles. The equilibrium constant for the formation of HI is (Atomic masses: H = 1 , I = 127 )

TestHub · Accepted Answer

H 2 ​ ( g ) + I 2 ​ ( g ) ⇌ 2 H I ( g ) Moles initially 15 5.2 0 Moles at equilibrium 15–5 5.2–5 10 Δ n = 0 hence So, K c ​ = [ 10 ] [ 5.2 ] 2 10 ​ = 50

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