Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumProblems involving more than one equilibriumEasy2 minQB
ChemistryEasynumerical
When N2O5(g) is heated to 500 K, it dissociates as: N2O5(g) ⇌ N2O3(g) + O2(g); KC = 5.0 M. Simultaneously, N2O3 decomposes as: N2O3(g) ⇌ N2O(g) + O2(g). When initially 8.0 moles of N2O5(g) is taken in a 2.0 L flask and allowed to attain equilibrium, the equilibrium concentration of O2(g) is found to be 5.0 M. The equilibrium concentration of N2O(g) (in M) is
Answer:
2.00
Solution:
Initial [N2O5] = 8.0/2.0 = 4.0 M Let a M of N2O5 dissociate and b M of N2O3 decompose
[N2O5] = 4 - a, [N2O3] = a - b, [N2O] = b, [O2] = a + b = 5
KC = (a-b)(5)/(4-a) = 5, so a - b = 4 - a
2a - b = 4 and a + b = 5
3a = 9, so a = 3 and b = 2
[N2O] = 2 M
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving more than one equilibrium
⏱ 2mℹ️ Source: QB
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