Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumDegree of Dissociation/Vapour Density/Molar MassEasy2 minQB
ChemistryEasynumerical
In a 10.0 L container, an equilibrium was established between SO3, SO2 and O2 gases, by starting with SO3 only. The density of equilibrium mixture was found to be 16 g/litre at a temperature of 800/0.0821 K. If the degree of dissociation of SO3 is 50%, then the value of KP (in atm) for the reaction: 2SO3(g) ⇌ 2SO2(g) + O2(g), is
Answer:
40.00
Solution:
Mass of mixture = (16)(10) = 160 g, so initial SO3 = 160/80 = 2 mol α = 0.5: SO3 = 1.0, SO2 = 1.0, O2 = 0.5, total = 2.5 mol
RT = (0.0821)(800/0.0821) = 800 L atm/mol
P = nRT/V = (2.5)(800)/10 = 200 atm
PSO3 = (1.0/2.5)(200) = 80 atm, PSO2 = (1.0/2.5)(200) = 80 atm, PO2 = (0.5/2.5)(200) = 40 atm
KP = (80)2(40)/(80)2 = 40
Answer is 0040
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Degree of Dissociation/Vapour Density/Molar Mass
⏱ 2mℹ️ Source: QB
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