0.3 mol H 2 and 0.2 mol I 2 are heated in a 1 L vessel at 444°C, where K c for H 2 ( g ) + I 2 ( g ) ⇌ 2 H I ( g ) is 49. The equilibrium amount of H I formed, in mol (up to two decimal plac

Question

0.3 mol H 2 ​ and 0.2 mol I 2 ​ are heated in a 1 L vessel at 444°C, where K c ​ for H 2 ​ ( g ) + I 2 ​ ( g ) ⇌ 2 H I ( g ) is 49. The equilibrium amount of H I formed, in mol (up to two decimal places), is

TestHub · Accepted Answer

Let x mol of H 2 ​ react: ( 2 x ) 2 / (( 0.3 − x ) ( 0.2 − x )) = 49 . 4 x 2 = 49 ( 0.06 − 0.5 x + x 2 ) , so 45 x 2 − 24.5 x + 2.94 = 0 . x = ( 24.5 − 8.43 ) /90 = 0.1786 (the other root, 0.366, exceeds 0.2 mol and is rejected). H I = 2 x = 0.357 , about 0.36 mol. Answer: 0.36.

Chemistry - Chemical Equilibrium Question with Solution | TestHub

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