Chemistry - Chemical Equilibrium Question with Solution | TestHub

Reaction 2 is half of reaction 1, so $K_2$ = √$K_1$, i.e. $K_1$ = $K_2^2$. Reaction 3 is the reverse of 1: $K_3$ = $1/K_1$. Reaction 4 is the reverse of 2: $K_4$ = $1/K_2$.

(A) $K_1$ x $K_3$ = 1: true.

(B) $K_2$ x $K_4$ = 1: true.

(C) $K_3$ x $K_2$ = $(1/K_1)$ x √$K_1$ = 1/√$K_1$, not 1: false.

(D) $K_1$ = $K_2^2$: true.

Answer: (A), (B), (D).