Chemistry - Chemical Equilibrium Question with Solution | TestHub

$N{H}_{2}COON{H}_4(s)\rightleftharpoons 2N{H}_3(g)+C{O}_2(g)$

Moles initially: 1 0 0

Moles at equilibrium: $(1-x)$ $2x$ $x$

Total moles of gaseous species at equilibrium = $3x$.

The equilibrium pressure is $P_T$.

$P_{N{H}_3}=\frac{2}{3}{P}_T$ ; $P_{C{O}_2}=\frac{1}{3}{P}_T$

$K_p=P_{N{H}_3}^2{P}_{C{O}_2}={\left(\frac{2}{3}{P}_T\right)}^2\left(\frac{1}{3}{P}_T\right)$

$3.2\times 10^{-5}=\frac{4{\left(P_T\right)}^3}{27}$

$P_T=0.06atm$