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ChemistryChemical EquilibriumProblems involving KpMedium2 minQB
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When a mixture of N2 and H2 in the volume ratio 1:3 reacts at 10 atm total pressure, the equilibrium mixture contains 0.2 mole fraction of NH3. The Kp for N2(g) + 3H2(g) ⇌ 2NH3(g) is
Options:
Answer:
A
Solution:
Start with 1 mol N2 and 3 mol H2; at equilibrium N2 = 1-x, H2 = 3-3x, NH3 = 2x, total = 4-2x 2x/(4-2x) = 0.2, so x = 1/3
Mole fractions: NH3 = 0.2, N2 = 0.2, H2 = 0.6
Kp = ((0.2)2)/((0.2)(0.6)3P2) = 0.926/((10)2)
Kp = 9.26×10-3 atm-2
This is option (a).
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kp
⏱ 2mℹ️ Source: QB
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