Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumProblems involving KcHard2 minQB
ChemistryHardsingle choice
Δf G° are 17.482 kJ/mol for gaseous isomer X and 10.000 kJ/mol for gaseous isomer Y, at 27°C. The molar ratio of X to Y at equilibrium at 27°C is [ln 20 = 3.0, R = 8.314 J/mol/K]
Options:
Answer:
C
Solution:
Y ⇌ X has Δ G° = 17.482 - 10.000 = 7.482 kJ/mol ln K = -Δ G°/RT = -7482/(8.314×300) = -3.0
K = [X]/[Y] = e-3.0 = 1/20
The X : Y ratio is 1 : 20
This is option (c).
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kc
⏱ 2mℹ️ Source: QB
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