Two gases A and D, at 2 atm and 3 atm respectively, are placed in a closed rigid container with an excess of B ( s ) and allowed to react as : 2 A ( g ) + B ( s ) ⇌ C ( g ) + E ( g ) : K P 1 A ( g

Question

Two gases A and D, at 2 atm and 3 atm respectively, are placed in a closed rigid container with an excess of $B (s)$ and allowed to react as :

$2 A (g) + B (s) ⇌ C (g) + E (g)$ : $K_{P_{1}}$

$A (g) + D (g) ⇌ 2 E (g)$ : $K_{P_{2}}$

If the equilibrium pressures of $C (g)$ and $E (g)$ gases are 1 atm and 2 atm respectively, then calculate

$K_{P_{1}} \times K_{P_{2}}$

TestHub · Accepted Answer

2 A ( g ) + B ( s ) ⇌ C ( g ) + E ( g ) : K P 1 ​ ​ x ( x + 2 y ) A ( g ) + D ( g ) ⇌ 2 E ( g ) : K P 2 ​ ​ 2 − x − y 3 − y ( x + 2 y ) × Since P C ​ = x = 1 and P E ​ = x + 2 y = 2 , we have: 1 + 2 y = 2 2 y = 1 y = 0.5 P A ​ = 2 − 1 − 2 1 ​ = 2 1 ​ P D ​ = 3 − 2 1 ​ = 2 5 ​ K P 1 ​ ​ = ( 2 1 ​ ) 2 1 × 2 ​ = 8 and K P 2 ​ ​ = ( 2 1 ​ × 2 5 ​ ) ( 2 ) 2 ​ = 5 16 ​ K P 1 ​ ​ × K P 2 ​ ​ = 25.6

Chemistry - Chemical Equilibrium Question with Solution | TestHub

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