In aqueous solution a sugar exists as two forms, X and Y, which interconvert. At equilibrium the solution contains 36.0% of Y and the rest is X. What is Δ G ° for the reaction X ⇌ Y at this temperatur

Question

In aqueous solution a sugar exists as two forms, X and Y, which interconvert. At equilibrium the solution contains 36.0% of Y and the rest is X. What is Δ G ° for the reaction X ⇌ Y at this temperature?

TestHub · Accepted Answer

At equilibrium Y is 36% and X is 64% K = [Y]/[X] = 36/64 = 0.5625

Δ G^° = -RTln K = -RTln(0.5625) = +RTln(1/0.5625)

1/0.5625 = 1.78, so Δ G^° = +RTln(1.78)

The natural logarithm is the one that appears in Δ G^° = -RTln K, and the sign is positive because K is less than 1

This is option (b).

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