NH 4 COONH 2 ( s ) ⇌ 2 NH 3 ( g ) + CO 2 ( g ) . If equilibrium pressure is 1 atm for the above reaction; K p will be:

Question

NH 4 ​ COONH 2 ​ ( s ) ⇌ 2 NH 3 ​ ( g ) + CO 2 ​ ( g ) . If equilibrium pressure is 1 atm for the above reaction; K p ​ will be:

TestHub · Accepted Answer

Total pressure P t o t a l ​ = P N H 3 ​ ​ + P C O 2 ​ ​ = 1 atm. From stoichiometry, P N H 3 ​ ​ = 2 P C O 2 ​ ​ . So, 2 P C O 2 ​ ​ + P C O 2 ​ ​ = 1 ⟹ 3 P C O 2 ​ ​ = 1 ⟹ P C O 2 ​ ​ = 1/3 atm. Then P N H 3 ​ ​ = 2/3 atm. K p ​ = ( P N H 3 ​ ​ ) 2 ( P C O 2 ​ ​ ) = ( 2/3 ) 2 ( 1/3 ) = ( 4/9 ) ( 1/3 ) = 4/27 .

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