Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumProblems involving KcEasy2 minQB
ChemistryEasysingle choice
Reaction: A(g) + B(g) ⇌ C(g) + D(g), occurs in a single step. The rate constant of forward reaction is 3.0 × 10-3 mol-1 L s-1. When the reaction is started with equimolar amounts of A and B, it is found that the concentration of A is 1.5 times that of C at equilibrium. The rate constant of the backward reaction is
Options:
Answer:
A
Solution:
Let a M each of A and B react to extent x: [A] = [B] = a - x, [C] = [D] = x a - x = 1.5x gives [A] = [B] = 1.5x and [C] = [D] = x
Kc = (x · x)/(1.5x · 1.5x) = 1/2.25 = 4/9
kb = kf/Kc = 3.0 × 10-3 × 9/4 = 6.75 × 10-3 mol-1 L s-1
This is option (a).
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kc
⏱ 2mℹ️ Source: QB
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