In a closed rigid vessel, the following equilibrium partial pressures are measured: N 2 = 200 mm, H 2 = 600 mm and NH 3 = 600 mm. Now, nitrogen is removed from the vessel until the pressure of hydroge

Question

In a closed rigid vessel, the following equilibrium partial pressures are measured: N 2 = 200 mm, H 2 = 600 mm and NH 3 = 600 mm. Now, nitrogen is removed from the vessel until the pressure of hydrogen at equilibrium is equal to 900 mm. The new equilibrium partial pressure of N 2 is

TestHub · Accepted Answer

N 2 + 3H 2 ⇌ 2NH 3 ; K p = 600 2 /(200 × 600 3 ) = 8.33 × 10 -6 mm -2 Removing N 2 shifts equilibrium left: H 2 rises from 600 to 900 mm (Δ = 300 mm) NH 3 falls by 2 × 300/3 = 200 mm to 400 mm P N2 = P NH3 2 /(K p · P H2 3 ) = 400 2 /(8.33 × 10 -6 × 900 3 ) P N2 = 160000/6075 = 26.3 mm This is option (a).

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