Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumDegree of Dissociation/Vapour Density/Molar MassHard2 minQB
ChemistryHardnumerical
The degree of dissociation of HI at a particular temperature is 0.5. Calculate the volume (in litre) of 0.5 M Na2S2O3 solution required to neutralize the iodine present in an equilibrium mixture of a reaction when 3 moles each of H2 and I2 are heated in a closed vessel of 3 L capacity.
Answer:
6.00
Solution:
For 2HI ⇌ H2 + I2 with α = 0.5, K = (α/2)2/(1-α)2 = (0.25)2/(0.5)2 = 0.25 For H2 + I2 ⇌ 2HI, Kc = 1/0.25 = 4
Let x mol of H2 react: H2 = I2 = 3 - x, HI = 2x
Kc = (2x)2/(3-x)2 = 4, so 2x/(3-x) = 2
4x = 6, so x = 1.5 mol
I2 left = 3 - 1.5 = 1.5 mol
I2 + 2S2O32- → 2I- + S4O62-, so thiosulfate needed = 3.0 mol
Volume = 3.0/0.5 = 6 L
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Degree of Dissociation/Vapour Density/Molar Mass
⏱ 2mℹ️ Source: QB
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