X dissociates as 2 X ( g ) ⇌ 2 Y ( g ) + Z ( g ) . When the initial pressure of X is 600 mm, the total pressure becomes 700 mm at equilibrium (constant volume). The K P (in mm) for the reaction 4 Y

Question

X dissociates as 2 X ( g ) ⇌ 2 Y ( g ) + Z ( g ) . When the initial pressure of X is 600 mm, the total pressure becomes 700 mm at equilibrium (constant volume). The K P ​ (in mm) for the reaction 4 Y ( g ) + 2 Z ( g ) ⇌ 4 X ( g ) is

TestHub · Accepted Answer

Let Z formed have pressure p . Total = 600 − 2 p + 2 p + p = 600 + p = 700 , so p = 100 . At equilibrium: X = 600 − 200 = 400 , Y = 200 , Z = 100 . K P ​ (forward) = ( 200 ) 2 ( 100 ) / ( 400 ) 2 = 25 . The required reaction is the reverse and doubled: K = ( 1/25 ) 2 = 1/625 = 1.6 × 1 0 − 3 . Trap: 25 is K for the forward reaction. Answer: (A).

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