Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumEffect of temperatureMedium2 minQB
ChemistryMediumnumerical
For the equilibrium: FeO(s) + CO(g) ⇌ Fe(s) + CO2(g), ΔG°(cal/mol) = -5300 - 7T(K). The temperature (in Kelvin) at which the gaseous mixture at equilibrium contains 200 ppm of CO, by mole, is [ln 10 = 2.3, ln 2 = 0.7; take R = 2 cal/mol/K]
Answer:
530.00
Solution:
Mole fraction of CO = 2 × 10-4, so mole fraction of CO2 ≈ 1 K = PCO2/PCO = 1/(2 × 10-4) = 5000
ln K = ln(104/2) = 4(2.3) - 0.7 = 8.5
ΔG° = -RT ln K = -(2)(T)(8.5) = -17T
-5300 - 7T = -17T
10T = 5300, so T = 530 K
Answer is 0530
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Effect of temperature
⏱ 2mℹ️ Source: QB
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