An unknown compound A dissociates at 500 ° C to give products as follows – A ( g ) ⇌ B ( g ) + C ( g ) + D ( g ) Vapour density of the equilibrium mixture is 50 when it dissociates to the extent to 10

Question

An unknown compound A dissociates at 500 ° C to give products as follows – A ( g ) ⇌ B ( g ) + C ( g ) + D ( g ) Vapour density of the equilibrium mixture is 50 when it dissociates to the extent to 10 % . What will be the molecular weight of Compound A–

TestHub · Accepted Answer

A g ⇌ B g + C g + D g α = Iintial vapour density − Vapour density at equilibrium moles of gaseous product × vapour density at equilbrium 1 10 = Vapour density − 50 3 − 1 50 Vapour density = 60 Molar mass of compound A = 2 × VD = 2 × 60 = 120 gm / mol

Chemistry - Chemical Equilibrium Question with Solution | TestHub

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