Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumProblems involving KpEasy2 minQB
ChemistryEasysingle choice
Solid ammonium carbamate dissociates as: NH2COONH4(s) ⇌ 2NH3(g) + CO2(g). In a closed vessel the solid is in equilibrium with its dissociation products. CO2 is then added such that the partial pressure of CO2 at the new equilibrium equals 4/3 times the original total pressure. The ratio of total pressure at the new equilibrium to the original total pressure is
Options:
Answer:
D
Solution:
Let the original total pressure be P, so PNH3 = 2P/3 and PCO2 = P/3 Kp = (2P/3)2(P/3) = 4P3/27
At the new equilibrium P'CO2 = 4P/3
(P'NH3)2 = Kp/P'CO2 = (4P3/27)×(3/4P) = P2/9
P'NH3 = P/3
P'total = P/3 + 4P/3 = 5P/3
P'total : P = 5 : 3
This is option (d).
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kp
⏱ 2mℹ️ Source: QB
Doubts & Discussion
Loading discussions...
