Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumProblems involving KcMedium2 minQB
ChemistryMediumsingle choice
Three moles of an equimolar mixture of two alcohols R1OH and R2OH are esterified with one mole of acetic acid. If 60% of the acid is consumed till equilibrium and the quantities of ester formed are in the ratio 2:1, the equilibrium constant for the esterification of R1OH is
Options:
Answer:
B
Solution:
Acid consumed = 0.6 mol, so total ester = 0.6 mol and water = 0.6 mol Ester ratio 2:1 gives ester of R1OH = 0.4 mol and of R2OH = 0.2 mol
At equilibrium acid = 0.4 mol and R1OH = 1.5 - 0.4 = 1.1 mol
K1 = ((0.4)(0.6))/((0.4)(1.1)) (volume cancels)
K1 = 0.55
This is option (b).
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kc
⏱ 2mℹ️ Source: QB
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