Match each dissociation in Column I with its K P (in atm) in Column II (a Column I entry may match more than one Column II entry): Column I (Dissociation) Column II ( K P in atm) (P) N 2 O 4 ⇌

Question

Match each dissociation in Column I with its $K_{P}$ (in atm) in Column II (a Column I entry may match more than one Column II entry):

Column I (Dissociation)	Column II ( $K_{P}$ in atm)
(P) $N_{2} O_{4} ⇌ 2 N O_{2}, α = 0.5$ at 1 atm	(1) $1/4$
(Q) $PC l_{5} ⇌ PC l_{3} + C l_{2}, α = 0.5$ at 1 atm	(2) $1/3$
(R) $N_{2} O_{4} ⇌ 2 N O_{2}, α = 0.2$ at 3 atm	(3) $1/2$
(S) $PC l_{5} ⇌ PC l_{3} + C l_{2}, α = 0.2$ at 6 atm	(4) $4/3$
	(5) $2/3$

Choose the option with the correct matching:

TestHub · Accepted Answer

N 2 ​ O 4 ​ : K P ​ = 4 α 2 P / ( 1 − α 2 ) . PC l 5 ​ : K P ​ = α 2 P / ( 1 − α 2 ) . (P) 4 ( 0.25 ) ( 1 ) /0.75 = 4/3 (4). (Q) 0.25/0.75 = 1/3 (2). (R) 4 ( 0.04 ) ( 3 ) /0.96 = 1/2 (3). (S) 0.04 ( 6 ) /0.96 = 1/4 (1). Correct matching: P to 4; Q to 2; R to 3; S to 1. Answer: (C).

Chemistry - Chemical Equilibrium Question with Solution | TestHub

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