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Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumDegree of Dissociation/Vapour Density/Molar MassMedium2 minQB

ChemistryMediumsingle choice

At the equilibrium of the reaction, $N_{2} O_{4} (g) ⇌ 2 NO_{2} (g)$ , the observed molar mass of the reaction mixture is 77.70 . The percentage dissociation of $N_{2} O_{4}$ is

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Answer:

Solution:

$α = \frac{D - d}{d}$ ; $α = \frac{92 - 77.7}{77.7} = 0.184$ ; % Dissociation = 18.4%

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Degree of Dissociation/Vapour Density/Molar Mass

⏱ 2mℹ️ Source: QB

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