4 . 5 moles each of hydrogen and iodine is heated in a sealed ten litre vessel.At equilibrium, 3 moles of HI were found. The equilibrium constant for H 2 g + I 2 g ⇌ 2 HI g is ........

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TestHub · Accepted Answer

The equilibrium moles of each reactant and product can be calculated as follows,

$H_{2} (g) + I_{2} (g) ⇌ 2 {HI}_{(g)} initial 4.5 4.5 0 At equilibrium 4.5 - 1.5 4.5 - 1.5 3$

Now, using equilibrium moles, equilibrium constant calculated as shown below.
$K_{eq} = \frac{[HI]^{2}}{[H_{2}] [I_{2}]} = \frac{(3)^{2}}{3 \times 3} = 1$

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