Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

When $A_{2}$ and $B_{2}$ are allowed to react, the equilibrium constant of the reaction at $27 ° C$ is found $(K_{C} = 4)$ .
$A_{2} (g) + B_{2} (g) ⇌ 2 A B (g)$
What will be the equilibrium concentration of AB?

Options:

Answer:

Solution:

$K_{C} = \frac{[A B]^{2}}{[A_{2}] [B_{2}]}$
$4 = \frac{[2 x / 4]^{2}}{(\frac{2 - x}{4}) (\frac{4 - x}{4})}$
$4 = \frac{4 x^{2}}{x^{2} - 6 x + 8}$
$x^{2} - 6 x + 8 = x^{2}$
$x = \frac{8}{6} = \frac{4}{3}$
$(A B) = \frac{2 x}{4} = \frac{2}{4} \times \frac{4}{3} = 0.66$ .

Stream:NTA_ABHYASSubject:ChemistryTopic:Chemical EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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