Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumProblems involving KpEasy2 minQB
ChemistryEasynumerical
The minimum mass (in g) of CaCO3 required to establish the equilibrium:
CaCO3(s) ⇌ CaO(s) + CO2(g), Kc = 0.03 M
at a certain temperature in a 2.0 L container is
Answer:
6.00
Solution:
Kc = [CO2] = 0.03 M Moles of CO2 needed in 2.0 L = (0.03)(2.0) = 0.06 mol
Minimum CaCO3 = 0.06 mol, since 1 mol CaCO3 gives 1 mol CO2
Mass = 0.06 × 100 = 6 g
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kp
⏱ 2mℹ️ Source: QB
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