3 moles of P and 2 moles of Q are allowed to react in a 5 L container: P + 2 Q ⇌ R . When equilibrium is reached, the concentration of R is 0.1 M. Calculate the equilibrium constant for this closed sy

Question

3 moles of P and 2 moles of Q are allowed to react in a 5 L container: P + 2 Q ⇌ R . When equilibrium is reached, the concentration of R is 0.1 M. Calculate the equilibrium constant for this closed system.

TestHub · Accepted Answer

Moles of R formed = 0.1 × 5 = 0.5 mol.

P used = 0.5 mol, left = 2.5 mol, so [P] = 0.5 M.

Q used = 2 × 0.5 = 1.0 mol, left = 1.0 mol, so [Q] = 0.2 M.

$K_{c}$ = $[R] / ([P] [Q]^{2})$ = 0.1/(0.5 × $0. 2^{2}$ ) = 0.1/0.02 = 5.

Answer: (C).

Chemistry - Chemical Equilibrium Question with Solution | TestHub

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