Chemistry - Chemical Equilibrium Question with Solution | TestHub

${\mathrm{PCl}}_5\rightleftharpoons {\mathrm{PCl}}_3+{\mathrm{Cl}}_2$

(1 − 𝛼) 𝛼 𝛼

Molecular weight of PCl₅ =$208.5D$.

The initial vapor density of PCl₅ is $D=\frac{208.5}{2}=104.25$.

The vapor density at equilibrium is $d=90$.

$\frac{D}{d}=\frac{(1+\alpha )}{1}$

$\alpha =\frac{D-d}{d}$

$\alpha =\frac{104.25-90}{90}=\frac{14.25}{90}=0.158$