Chemistry - Chemical Equilibrium Question with Solution | TestHub

$\mathrm{\text{N}}{\mathrm{\text{H}}}_2\mathrm{\text{C}}\mathrm{\text{O}}\mathrm{\text{O}}\mathrm{\text{N}}{\mathrm{\text{H}}}_4\left(\text{s}\right)\rightleftharpoons 2\mathrm{\text{N}}{\mathrm{\text{H}}}_3\left(\mathrm{\text{g}}\right)+\mathrm{\text{C}}{\mathrm{\text{O}}}_2\left(\mathrm{\text{g}}\right)$

At equilibrium if partial pressure of$\mathrm{\text{C}}{\mathrm{\text{O}}}_2\text{is } \text{p}$then that of$\mathrm{\text{N}}{\mathrm{\text{H}}}_3$is$2\text{p}$

So,${\text{K}}_{\text{p}}={\text{p}}_{{\mathit{\text{NH}}}_3}^2\times {\text{p}}_{{\mathit{\text{CO}}}_2}$

${\text{K}}_{\text{p}}={\left(2\text{p}\right)}^2\times \text{p}=4{\text{p}}^3$

$\text{2.9}\times {\text{10}}^{-5}=4{\text{p}}^3$

$\text{p}=\text{1.935}\times {\text{10}}^{-2}$

hence, total pressure$\text{p}=3\text{p}$

$=5.81\times {10}^{-2}=0.0581$atm.