Chemistry - Chemical Equilibrium Question with Solution | TestHub

As${\mathrm{K}}_{\mathrm{p}}={\mathrm{K}}_{\mathrm{c}}$is possible when${\mathrm{n}}_{\mathrm{P}}={\mathrm{n}}_{\mathrm{R}}$
Here in case of$2{\mathrm{C}}_{\left(\mathrm{s}\right)}+{\mathrm{O}}_{2\left(\mathrm{g}\right)}\rightleftharpoons 2\mathrm{C}{\mathrm{O}}_{2\left(\mathrm{g}\right)}$
${\mathrm{n}}_{\mathrm{P}}=2,{\mathrm{n}}_{\mathrm{R}}=1$
So$\mathrm{\Delta }{\mathrm{n}}_{\mathrm{g}}=2-1=1$
${\mathrm{K}}_{\mathrm{p}}={\mathrm{K}}_{\mathrm{c}}(\mathrm{R}\mathrm{T}{)}^1$
${\mathrm{K}}_{\mathrm{p}}>{\mathrm{K}}_{\mathrm{c}}$