Chemistry - Chemical Equilibrium Question with Solution | TestHub

$\Delta {\text{G}}_{\text{A}}^{\circ }=-{\text{2.303 RT log}}_{10}{\text{K}}_{\text{A}}$

$\Delta {\text{G}}_{\text{B}}^{\circ }=-{\text{2.303 RT log}}_{10}{\text{K}}_{\text{B}}$

$\therefore \frac{\Delta {\text{G}}_{\text{A}}^{\circ }}{\Delta {\text{G}}_{\text{B}}^{\circ }}={\text{log}}_{10}\frac{{\text{K}}_{\text{A}}}{{\text{K}}_{\text{B}}}$

$4={\text{log}}_{10}\frac{{\text{K}}_{\text{A}}}{{\text{K}}_{\text{B}}}$

$\therefore \frac{{\text{K}}_{\text{A}}}{{\text{K}}_{\text{B}}}=10^4=10000$