Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

Plot of log (x/m) against log P is a straight line inclined at an angle $45^{o} .$ When the pressure is 0.5 atm and Freundich parameter k is 10, the amount of solute adsorbed per gram of adsorbent will be (log5 = 0.699)

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Answer:

Solution:

$log (x/m) = log k + 1/n log P$
$1/n = tan 45^{o} = 1; log k = log 10 = 1$
$x/m = {kp}^{\frac{1}{n}} = 10* (0 .5) 1 = 5$
When $m = 1 g, x = 5 g$

Stream:NTA_ABHYASSubject:ChemistryTopic:Chemical EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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