Plot of log (x/m) against log P is a straight line inclined at an angle 45 o . When the pressure is 0.5 atm and Freundich parameter k is 10, the amount of solute adsorbed per gram of adsorbent will be

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Plot of log (x/m) against log P is a straight line inclined at an angle 45 o . When the pressure is 0.5 atm and Freundich parameter k is 10, the amount of solute adsorbed per gram of adsorbent will be (log5 = 0.699)

TestHub · Accepted Answer

log x/m = log k + 1/n log P 1/n = tan 45 o = 1; log k = log 10 = 1 x/m = kp 1 n = 10* 0 .5 1 = 5 When m = 1 g, x = 5 g

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