Densities of diamond and graphite are 3.5 and 2.3 gm / mL . C ( diamond ) → C (graphite) Δ r H = − 1.9 k J / mole favourable conditions for formation of diamond are

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ChemistryChemical EquilibriumLe-Chatelier's PrincipleMedium2 minQB

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Densities of diamond and graphite are 3.5 and $2.3 gm / mL$ .

$C (diamond) \to C (graphite) Δ_{r} H = - 1.9 k J / mole$

favourable conditions for formation of diamond are

Options:

Answer:

Solution:

Since the process is exothermic, On increasing the temperature, the reaction moves backwards favouring the formation of Diamond. Also, on increasing the pressure, more denser phase(diamond) will be formed.

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Le-Chatelier's Principle

⏱ 2mℹ️ Source: QB

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