Chemistry - Chemical Equilibrium Question with Solution | TestHub

For the reaction $$\begin{array}{r}2{\mathrm{BaO}}_2(s)\rightleftharpoons 2\mathrm{BaO}(s)+{\mathrm{O}}_2(\mathrm{g})\\ \Delta \mathrm{H}=+\text{ ve. }\end{array}$$ In equilibrium ${\mathrm{K}}_{\mathrm{p}}={\mathrm{P}}_{{\mathrm{O}}_2}$ Hence, the value of equilibrium constant depends only upon partial pressure of ${\mathrm{O}}_2$. Further on increasing temperature formation of ${\mathrm{O}}_2$ increases as this is an endothermic reaction. Hence, pressure of ${\mathrm{O}}_2$ is dependent on temperature.