If the equilibrium constant for N 2 g + O 2 ( g ) ⇌ 2 N O ( g ) is K, the equilibrium constant for 1 2 N 2 g + 1 2 O 2 ( g ) ⇌ N O ( g ) will be:NEET 2015 (Phase 2)

N 2 ( g ) + O 2 ( g ) ⇌ 2 NO ( g ) ; K 2 1 N 2 ( g ) + 2 1 O 2 ( g ) ⇌ NO ( g ) ; K ′ K = [ N 2 ] [ O 2 ] [ NO 2 K ′ = [ N 2 ] 1/2 [ O 2 ] 1/2 NO ∴ K ′ = K

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ChemistryChemical EquilibriumMiscellaneous/MixedMedium2 minPYQ_2015

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If the equilibrium constant for $N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)$ is K, the equilibrium constant for $\frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ N O (g)$ will be:NEET 2015 (Phase 2)

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Solution:

$N_{2} (g) + O_{2} (g) ⇌ 2 NO (g); K \frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ NO (g); K^{'} K = \frac{[ NO ^{2}}{[ N _{2} ] [ O _{2} ]} K^{'} = \frac{NO}{[ N _{2} ] ^{1/2} [ O _{2} ] ^{1/2}} ∴ K^{'} = K$

Stream:NEETSubject:ChemistryTopic:Chemical EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2015

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