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Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumMiscellaneous/MixedMedium2 minPYQ_2007

ChemistryMediumsingle choice

Equivalent amounts of $H_{2}$ and $I_{2}$ are heated in a closed vessel till equilibrium is obtained. If $80%$ of the hydrogen can be converted to $HI$ , the $Kc$ at this temperature is

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Answer:

Solution:

$K_{c} = \frac{[ HI ] ^{2}}{[ H _{2} ] [ I _{2} ]} = \frac{( 2 x ) ^{2}}{( 1 - x ) ^{2}}$ Given $x = 80% = 0.80$ $∴ K_{c} = \frac{( 2 \times 0.80 ) ^{2}}{( 1 - 0.80 ) ^{2}} = 64$

Stream:VITEEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2007

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