Given that the equilibrium constant for the reaction $2 S O_{2 (g)} + O_{2 (g)} ⇌ 2 S O_{3 (g)}$ has a value of 278 at a particular temperature. What is the value of the equilibrium constant for the following reaction at the same temperature?

$S O_{3 (g)} ⇌ S O_{2 (g)} + \frac{1}{2} O_{2 (g)}$

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TestHub · Accepted Answer

At the given temperature, 2 S O 2 + O 2 ⇌ 2 S O 3 K = [ S O 3 ] 2 [ S O 2 ] 2 [ O 2 ] S O 3 ⇌ S O 2 + 1 2 O 2 K ′ = [ S O 2 ] [ O 2 ] 1 2 [ S O 2 ] K ′ = 1 K = 1 278 = 35.97 × 10 − 4 = 6 × 10 − 2

Chemistry - Chemical Equilibrium Question with Solution | TestHub

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