Out of given orbitals, find the total number of orbital(s) used for hybridisation (by B & P atoms) in $BF_{3}$ & $PF_{5}$ molecules:
2s, 2pₓ, 2pᵧ, 2p𝓏, 3s, 3pₓ, 3pᵧ, 3p𝓏, 3dₓᵧ, 3dᵧ𝓏, 3dₓ𝓏, 3dₓ²₋ᵧ², 3d𝓏²

Question

Out of given orbitals, find the total number of orbital(s) used for hybridisation (by B & P atoms) in $BF_{3}$ & $PF_{5}$ molecules:

2s, 2pₓ, 2pᵧ, 2p𝓏, 3s, 3pₓ, 3pᵧ, 3p𝓏, 3dₓᵧ, 3dᵧ𝓏, 3dₓ𝓏, 3dₓ²₋ᵧ², 3d𝓏²

TestHub · Accepted Answer

In BF₃, Boron is sp² hybridised, using 2s, 2pₓ, 2pᵧ → total 3 orbitals.
In PF₅, Phosphorus is sp³d hybridised, using 3s, 3pₓ, 3pᵧ, 3p𝓏, 3dₓ𝓏 (or any one 3d orbital) → total 5 orbitals.

Now count distinct orbitals used from the given list:
BF₃ → 3 orbitals (2s, 2pₓ, 2pᵧ)
PF₅ → 5 orbitals (3s, 3pₓ, 3pᵧ, 3p𝓏, 3d)

Total unique orbitals used = 8

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