CHEM_REMOVED - CHEMICAL BONDING Question with Solution | TestHub

An odd electron bond means there is an odd number of the electron in the overall molecule. Or we can say that the molecule has unpaired electrons.

So, in $\mathrm{NO}$, the valence electrons in nitrogen are $5$, and valence electrons in oxygen are $6$. So, by adding we get, $6+5=11$

In sulfuric acid $\left({\mathrm{H}}_2{\mathrm{SO}}_4\right)$, each oxygen has a full octet (eight valence electrons), whereas sulfur has an expanded octet (twelve valence electrons).

(A) ${\mathrm{BCl}}_3\to$ Even Electron molecule ${\mathrm{SF}}_6\to$ Expanded octet molecule

(B) $\mathrm{NO}\to$ Odd Electron molecule ${\mathrm{H}}_2{\mathrm{SO}}_4\to$ Expanded octet.

(C) ${\mathrm{SF}}_6\to$ Even Electron molecule ${\mathrm{H}}_2{\mathrm{SO}}_4\to$ Expanded octet.

(D) ${\mathrm{BCl}}_3\to$ Even Electron molecule $\mathrm{NO}\to$ Odd Electron molecule