Consider the following sulfur oxyanions: S 2 O 3 ²⁻, S 2 O 4 ²⁻, S₂O 5 ²⁻, S₂O 6 ²⁻, S₂O₇²⁻, S₂O₈²⁻, S₄O₆²⁻, S₅O₆²⁻. Let X , Y , and Z be defined as follows: * X = Number of anions in which a bond bet

Question

Consider the following sulfur oxyanions:

S₂O₃²⁻, S₂O₄²⁻, S₂O₅²⁻, S₂O₆²⁻, S₂O₇²⁻, S₂O₈²⁻, S₄O₆²⁻, S₅O₆²⁻.

Let $X$ , $Y$ , and $Z$ be defined as follows:

* $X$ = Number of anions in which a bond between two identical atoms is present.

* $Y$ = Number of anions in which all oxygen atoms have the same oxidation state.

* $Z$ = Number of anions that contain an oxo-bridge.

Calculate the value of $X + Y + Z$ .

TestHub · Accepted Answer

Final values: X = 7 (S₂O₃²⁻, S₂O₄²⁻, S₂O₅²⁻, S₂O₆²⁻, S₂O₈²⁻, S₄O₆²⁻, S₅O₆²⁻) Y = 7 (S₂O₃²⁻, S₂O₄²⁻,S₂O 5 ²⁻, S₂O₆²⁻, S₂O₇²⁻, S₄O₆²⁻, S₅O₆²⁻) Z = 1 (S₂O₇²⁻) X + Y + Z = 7 + 7 + 1 = 15 .

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