A diatomic molecule has a dipole moment of 1.92 D and a bond length of
$2.0$ Å. What is the percentage ionic character in the molecule if $e = 4.8 \times 1 0^{- 10}$ esu?

Question

A diatomic molecule has a dipole moment of 1.92 D and a bond length of 2.0 Å. What is the percentage ionic character in the molecule if e = 4.8 × 1 0 − 10 esu?

TestHub · Accepted Answer

% ionic characters = calculated dipole moment assumin g100% i o ni c C ha r a c t er observed dipole moment ​ × 100 % I o ni c C ha r a c t er = ( 4.80 × 1 0 − 10 ) × ( 2 × 1 0 − 8 c m ) 1.92 D ​ × 100 I o ni c C ha r a c t er = ( 4.8 × 2 ) D 1.92 D ​ × 100 = 20%

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