Chemistry - CHEMICAL BONDING Question with Solution | TestHub

${\mathrm{Na}}_2{\mathrm{S}}_2{\mathrm{O}}_3\cdot 5{\mathrm{H}}_2\mathrm{O}⟶{\mathrm{Na}}_2{\mathrm{S}}_2{\mathrm{O}}_3+5{\mathrm{H}}_2\mathrm{O}$

$4{\mathrm{Na}}_2{\mathrm{S}}_2{\mathrm{O}}_3\stackrel{\Delta }{\to }3\underset{(X)}{{\mathrm{Na}}_2{\mathrm{SO}}_4}+\underset{(Y)}{{\mathrm{Na}}_2{\mathrm{S}}_5}$

$\therefore a=4,b=4$