Match the column. Column I Coulmn II (1) S F 2 (p) s p 3 and bent (2) X e F 4 (q) Two lone pairs on central atom (3) N O C l (r) Bond angle < 109.5 ° (4) N F 3 (s) s p 2 and bent (t) s p 3 d 2 and square planar

S F 2 → s p 3 θ < 109.208 (bent) X e F 4 → s p 3 d (Square planar) N O C l → s p 2 (bent) N F 3 → s p 3 (Pyramidal)

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGMiscellaneous/MixedEasy2 minPYQ_2020

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Match the column.

Column I		Coulmn II
(1)	$S F_{2}$	(p)	$s p^{3}$ and bent
(2)	$X e F_{4}$	(q)	Two lone pairs on central atom
(3)	$N O C l$	(r)	Bond angle $< 109.5 °$
(4)	$N F_{3}$	(s)	$s p^{2}$ and bent
		(t)	$s p^{3} d^{2}$ and square planar

Answer:

Solution:

$S F_{2} \to s p^{3}$ $θ < 109.208$ (bent)
$X e F_{4} \to s p^{3} d$ (Square planar)
$N O C l \to s p^{2}$ (bent)
$N F_{3} \to s p^{3}$ (Pyramidal)

Stream:NTA_ABHYASSubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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