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Passage / Comprehension

Column-I (Compounds)	Column-II (Characteristics)	Column-III (Characteristics)
(P) $Na_{2} B_{2} O_{4} (OH)_{4}$	(1) Contains even number of $π$ -bonds	(i) Contains X-O-X linkage
(Q) $Na_{2} B_{4} O_{5} (OH)_{4}$	(2) Contains odd number of $π$ -bonds	(ii) Has cyclic structure
(R) $C_{3} N_{3} (NH_{2})_{3}$	(3) No $π$ -bonds are present	(iii) Has $\geq 2 sp^{2}$ hybridised atoms
(S) $Na_{6} [(PO_{3})_{6}]$	(4) Has ionic bond	(iv) Has $\leq 3 sp^{3}$ hybridised atoms

Select the CORRECT combination :

Options:

Answer:

Solution:

The correct combination is (D) Q - 4 - (ii) based on the following structural analysis:

Compound Q Identification: Na₂B₄O₅(OH)₄ is the anionic representation of borax, containing Na⁺ cations and $[B_{4} O_{5} (O H)_{4}]$ ²⁻ anions.

Column-II Verification (4): The electrostatic attraction between the sodium cations and the borate anions confirms it has an ionic bond.

Column-III Verification (ii): The complex anion $[B_{4} O_{5} (O H)_{4}]$ ²⁻ contains two fused six-membered B-O rings, confirming it has a cyclic structure.

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

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Doubts & Discussion