Chemistry - CHEMICAL BONDING Question with Solution | TestHub
ChemistryCHEMICAL BONDINGVSEPR, Bond Angle, Bond Length, Bond EnergyMedium2 minQB
ChemistryMediuminteger
Find the number of
bond angle(s) in above structure.
Answer:
6
Solution:
The structure shown is basic beryllium acetate, Be₄O(CH₃COO)₆, where a central oxygen atom () is tetrahedrally coordinated to four beryllium atoms (Be).
The four Be atoms form the vertices of a regular tetrahedron.
The oxygen atom () sits at the exact center of this tetrahedron.
In a regular tetrahedron, the number of edges connecting the vertices is 6.
Each edge corresponds to one Be--Be bond angle centered at the oxygen atom.
Therefore, the number of such bond angles is 6.
Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:VSEPR, Bond Angle, Bond Length, Bond Energy
⏱ 2mℹ️ Source: QB
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