Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGMOTEasy2 minPYQ_2020
ChemistryEasysingle choice

The bond length inO2+,O2,O2-andO22-follows the order

Options:

Answer:
A
Solution:

O2-2=σ1s2<σ*1s2<σ2s2<σ*2s2<σ2px2<π2py2=π2pz2<π*2py2=π*2pz2

B.O.=nb-na2=6-42=1

O2-=σ1s2<σ*1s2<σ2s2<σ*2s2<σ2px2<π2py2=π2pz2<π*2py2=π*2pz1

B.O.=6-32=1.5

O2=σ1s2<σ*1s2<σ2s2<σ*2s2<σ2px2<π2pz2=π2py2<π*2py1=π*2pz1

B.O.=6-22=2

O2+=σ1s2<σ*1s2<σ2s2<σ*2s2<σ2px2<π2pz2=π2py2<π*2py1=π*2pz0

B.O.=6-12=2.5

Bond length∝1Bond order

Bond lengthO2-2>O2->O2>O2+

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:MOT
⏱ 2mℹ️ Source: PYQ_2020

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