Chemistry - CHEMICAL BONDING Question with Solution | TestHub

M.O. configuration of${\mathrm{N}}_2$is
${\left(\mathrm{\sigma }\text{1s}\right)}^2{\left(\mathrm{\sigma }\mathrm{*}\text{1s}\right)}^2{\left(\mathrm{\sigma }\text{2s}\right)}^2{\left(\mathrm{\sigma }\mathrm{*}\text{2s}\right)}^2{\left(\mathrm{\pi }\text{2}{\text{p}}_{\mathrm{x}}\right)}^2{\left(\mathrm{\pi }\text{2}{\text{p}}_{\mathrm{y}}\right)}^2{\left(\mathrm{\sigma }\text{2}{\text{p}}_{\mathrm{z}}\right)}^1$
B.O. of${\mathrm{N}}_2=\frac{10-4}{2}=3$
M.O. configuration of${\mathrm{N}}_2^{+}$is
${\left(\mathrm{\sigma }\text{1s}\right)}^2{\left(\mathrm{\sigma }\mathrm{*}\text{1s}\right)}^2{\left(\mathrm{\sigma }\text{2s}\right)}^2{\left(\mathrm{\sigma }\mathrm{*}\text{2s}\right)}^2{\left(\mathrm{\pi }\text{2}{\text{p}}_{\mathrm{x}}\right)}^2{\left(\mathrm{\pi }\text{2}{\text{p}}_{\mathrm{y}}\right)}^2{\left(\mathrm{\sigma }\text{2}{\text{p}}_{\mathrm{z}}\right)}^1$
B.O. of${\mathrm{N}}_2^{+}=\frac{9-4}{2}=2.5$
Hence,${\mathrm{N}}_2^{+}$becomes paramagnetic so statement 2 is incorrect
M.O. of configuration of${\mathrm{O}}_2$is
${\left(\mathrm{\sigma }\text{1s}\right)}^2{\left(\mathrm{\sigma }\mathrm{*}\text{1s2}\right)}^2{\left(\mathrm{\sigma }\text{2s}\right)}^2{\left(\mathrm{\sigma }\mathrm{*}\text{2s}\right)}^2{\left(\mathrm{\sigma }\text{2}{\text{p}}_{\mathrm{z}}\right)}^2{\left(\mathrm{\pi }\text{2}{\text{p}}_{\mathrm{x}}\right)}^2{\left(\mathrm{\pi }\text{2}{\text{p}}_{\mathrm{y}}\right)}^2\mathrm{}{\left(\mathrm{\pi }\mathrm{*}\text{2}{\text{p}}_{\mathrm{x}}\right)}^1{\left(\mathrm{\pi }\mathrm{*}\text{2}{\text{p}}_{\mathrm{y}}\right)}^1$
So B.O. of${\mathrm{O}}_2=\frac{10–6}{2}=2$
M.O. configuration of${\mathrm{O}}_2^{+}$is
${\left(\mathrm{\sigma }\text{1s}\right)}^2{\left(\mathrm{\sigma }\mathrm{*}\text{1s}\right)}^2{\left(\mathrm{\sigma }\text{2s}\right)}^2{\left(\mathrm{\sigma }\mathrm{*}\text{2s}\right)}^2{\left(\mathrm{\sigma }\text{2}{\text{p}}_{\mathrm{z}}\right)}^2{\left(\mathrm{\pi }\text{2}{\text{p}}_{\mathrm{x}}\right)}^2{\left(\mathrm{\pi }\text{2}{\text{p}}_{\mathrm{y}}\right)}^2{\left(\mathrm{\pi }\mathrm{*}\text{2}{\text{p}}_{\mathrm{x}}\right)}^1$
B.O. of${\mathrm{O}}_2^{+}=\frac{10-5}{2}=2.5$
$\text{B}\text{.O}\text{.}\propto \text{Bond}\text{energy}\propto \frac{\text{1}}{\text{Bond}\text{length}}$